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Put a flat earthier into space

Since the gravy stained melt has me on ignore, can someone ask him where these rockets actually go if not into space?
 

more narrative

Wonder if it looks like a lemon squeezer.
Will just look round now as everything far away turns into a circle obviously.
Since the gravy stained melt has me on ignore, can someone ask him where these rockets actually go if not into space?
Rockets?
Surely if you've watched space 1999 that therefore means they don't really exist.
 
Since the gravy stained melt has me on ignore, can someone ask him where these rockets actually go if not into space?
I've heard them say that the astronauts enter the rockets and leave via a secret door, before takeoff, then the rocket takes of and ditches miles away at see, there's umpteen YouTube videos where they state this... f***ing hilarious. There's even a video where they state that nobody died on the challenger shuttle disaster, and are living there lives in secret.
 
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I've heard them say that the astronauts enter the rockets and leave via a secret door, before takeoff, then the rocket takes of and ditches miles away at see, there's umpteen YouTube videos where they state this... f***ing hilarious.

Imagine training for years only to be told to jump through a stage trapdoor just before the most significant moment in your life and it’s all a sham.
 
Imagine training for years only to be told to jump through a stage trapdoor just before the most significant moment in your life and it’s all a sham.
They were actually tracking down people with the same names as the dead astronauts and confronting them.
 
I don't know. I don't think the whole world is. The world is what it is and it's real. The issue is in us understanding what it is, exactly.
I know what it is not (it's not a spinning globe) it's just a case of figuring out what the entire reality is, which we may never know for sure.

I reckon this is what he Universe looks like, what do you think mate?

 
Sorry if you've already responded to this request, but could you give a link or directions to other experiments that have been carried out that prove the earths flatness?
Go and do it yourself. Water level.
Go and try it anywhere you like.
Use whatever you like as a container and even unbalance it and watch teh water level up.
You know this but you choose to believe it conforms to a globe because that's the narrative set out in mainstream. Simple as that really.
I may just do that, but in the meantime can you direct me to anything where anyone has done this - using water I mean.
Do it for you not for anyone else. You can look for whatever you want. You do not need me to hold your hand.
I’m simply asking for your help.
Can you direct me to any of these experiments?
It would be interesting to see what others had acheived.
 
Here's something for you to get your teeth into. Let's see if you go for the mirage clap trap.


You denied the 8 inches per mile, squared.
8 inches per mile squared is wrong, but interestingly when you look at it, it is a reasonable rule of thumb for less than 100 miles, on a planet of the size of earth.

Mixing feet, inches and miles does muddy the water a bit, because imperial just gets odd and frustrating, but when you compare the rule I put forward (and someone agreed with above) over relative short distances they are actually pretty close. However the further and further distance, the more inaccurate it becomes:
Distance in milesDistance in kmDrop in feet by sq rule (feet)metersDrop by reality (KM)in feetDifference
3556.3816.7248.920.24900816.91-0.2
3657.9864.0263.30.26343864.26-0.3
3759.5912.7278.20.27826912.94-0.3
3861.2962.7293.40.29351962.96-0.3
3962.81014.0309.10.309161014.31-0.3
4064.41066.7325.10.325221066.99-0.3
4166.01120.7341.60.341681121.00-0.3
4267.61176.0358.40.358551176.35-0.4
4369.21232.7375.70.375831233.04-0.4
4470.81290.7393.40.393511291.05-0.4
4572.41350.0411.50.411601350.40-0.4
4674.01410.7430.00.430101411.09-0.4
4775.61472.7448.90.449001473.10-0.4
4877.21536.0468.20.468311536.46-0.5
4978.91600.7487.90.488031601.14-0.5
5080.51666.7508.00.508151667.16-0.5
5182.11734.0528.50.528681734.51-0.5
5283.71802.7549.50.549611803.20-0.5
5385.31872.7570.80.570961873.22-0.6
5486.91944.0592.50.592711944.57-0.6
5588.52016.7614.70.614862017.26-0.6
5690.12090.7637.20.637422091.28-0.6
5791.72166.0660.20.660392166.63-0.6
5893.32242.7683.60.683762243.32-0.7
5995.02320.7707.30.707542321.34-0.7
6096.62400.0731.50.731732400.70-0.7
6198.22480.7756.10.756332481.38-0.7
6299.82562.7781.10.781332563.41-0.7
63101.42646.0806.50.806732646.76-0.8
64103.02730.7832.30.832552731.45-0.8
65104.62816.7858.50.858772817.47-0.8
66106.22904.0885.10.885392904.83-0.8
67107.82992.7912.20.912432993.52-0.9
68109.43082.7939.60.939863083.54-0.9
69111.03174.0967.40.967713174.90-0.9
70112.73266.7995.70.995963267.59-0.9
71114.33360.71024.31.024623361.62-0.9

You can see from the table above that over 50 miles it is pretty close, I ended my table on 71 miles and you can see that your approximation gets further and further away.

Now, my rule came about from me sitting with pencil and paper along with basic rules of trigonometry and working it out from first principals. As a result I can explain exactly how it works.

Is your rule something you have found on the internet by any chance, something you feel you have been schooled into believing perhaps?

Lets forget about Earth for a moment. If I asked your to provide a rule for the circular drop of any planet of radius r over a distance of d, what would your formula be?

But if you can't do that, suppose your method is correct, what would be the circular drop on earth be on something the length of a bath? Can you work that out and tell us how much the globe model earth drop by over 1.5m (or 5 feet in ancient language)?
 
8 inches per mile squared is wrong, but interestingly when you look at it, it is a reasonable rule of thumb for less than 100 miles, on a planet of the size of earth.

Mixing feet, inches and miles does muddy the water a bit, because imperial just gets odd and frustrating, but when you compare the rule I put forward (and someone agreed with above) over relative short distances they are actually pretty close. However the further and further distance, the more inaccurate it becomes:
Distance in milesDistance in kmDrop in feet by sq rule (feet)metersDrop by reality (KM)in feetDifference
3556.3816.7248.920.24900816.91-0.2
3657.9864.0263.30.26343864.26-0.3
3759.5912.7278.20.27826912.94-0.3
3861.2962.7293.40.29351962.96-0.3
3962.81014.0309.10.309161014.31-0.3
4064.41066.7325.10.325221066.99-0.3
4166.01120.7341.60.341681121.00-0.3
4267.61176.0358.40.358551176.35-0.4
4369.21232.7375.70.375831233.04-0.4
4470.81290.7393.40.393511291.05-0.4
4572.41350.0411.50.411601350.40-0.4
4674.01410.7430.00.430101411.09-0.4
4775.61472.7448.90.449001473.10-0.4
4877.21536.0468.20.468311536.46-0.5
4978.91600.7487.90.488031601.14-0.5
5080.51666.7508.00.508151667.16-0.5
5182.11734.0528.50.528681734.51-0.5
5283.71802.7549.50.549611803.20-0.5
5385.31872.7570.80.570961873.22-0.6
5486.91944.0592.50.592711944.57-0.6
5588.52016.7614.70.614862017.26-0.6
5690.12090.7637.20.637422091.28-0.6
5791.72166.0660.20.660392166.63-0.6
5893.32242.7683.60.683762243.32-0.7
5995.02320.7707.30.707542321.34-0.7
6096.62400.0731.50.731732400.70-0.7
6198.22480.7756.10.756332481.38-0.7
6299.82562.7781.10.781332563.41-0.7
63101.42646.0806.50.806732646.76-0.8
64103.02730.7832.30.832552731.45-0.8
65104.62816.7858.50.858772817.47-0.8
66106.22904.0885.10.885392904.83-0.8
67107.82992.7912.20.912432993.52-0.9
68109.43082.7939.60.939863083.54-0.9
69111.03174.0967.40.967713174.90-0.9
70112.73266.7995.70.995963267.59-0.9
71114.33360.71024.31.024623361.62-0.9

You can see from the table above that over 50 miles it is pretty close, I ended my table on 71 miles and you can see that your approximation gets further and further away.

Now, my rule came about from me sitting with pencil and paper along with basic rules of trigonometry and working it out from first principals. As a result I can explain exactly how it works.

Is your rule something you have found on the internet by any chance, something you feel you have been schooled into believing perhaps?

Lets forget about Earth for a moment. If I asked your to provide a rule for the circular drop of any planet of radius r over a distance of d, what would your formula be?

But if you can't do that, suppose your method is correct, what would be the circular drop on earth be on something the length of a bath? Can you work that out and tell us how much the globe model earth drop by over 1.5m (or 5 feet in ancient language)?
Excellent but being pedantic asking him to do the maths for a planet is pejorative, he can have less complaint if asked to work it out for a globe of that size
 
8 inches per mile squared is wrong, but interestingly when you look at it, it is a reasonable rule of thumb for less than 100 miles, on a planet of the size of earth.

Mixing feet, inches and miles does muddy the water a bit, because imperial just gets odd and frustrating, but when you compare the rule I put forward (and someone agreed with above) over relative short distances they are actually pretty close. However the further and further distance, the more inaccurate it becomes:
Distance in milesDistance in kmDrop in feet by sq rule (feet)metersDrop by reality (KM)in feetDifference
3556.3816.7248.920.24900816.91-0.2
3657.9864.0263.30.26343864.26-0.3
3759.5912.7278.20.27826912.94-0.3
3861.2962.7293.40.29351962.96-0.3
3962.81014.0309.10.309161014.31-0.3
4064.41066.7325.10.325221066.99-0.3
4166.01120.7341.60.341681121.00-0.3
4267.61176.0358.40.358551176.35-0.4
4369.21232.7375.70.375831233.04-0.4
4470.81290.7393.40.393511291.05-0.4
4572.41350.0411.50.411601350.40-0.4
4674.01410.7430.00.430101411.09-0.4
4775.61472.7448.90.449001473.10-0.4
4877.21536.0468.20.468311536.46-0.5
4978.91600.7487.90.488031601.14-0.5
5080.51666.7508.00.508151667.16-0.5
5182.11734.0528.50.528681734.51-0.5
5283.71802.7549.50.549611803.20-0.5
5385.31872.7570.80.570961873.22-0.6
5486.91944.0592.50.592711944.57-0.6
5588.52016.7614.70.614862017.26-0.6
5690.12090.7637.20.637422091.28-0.6
5791.72166.0660.20.660392166.63-0.6
5893.32242.7683.60.683762243.32-0.7
5995.02320.7707.30.707542321.34-0.7
6096.62400.0731.50.731732400.70-0.7
6198.22480.7756.10.756332481.38-0.7
6299.82562.7781.10.781332563.41-0.7
63101.42646.0806.50.806732646.76-0.8
64103.02730.7832.30.832552731.45-0.8
65104.62816.7858.50.858772817.47-0.8
66106.22904.0885.10.885392904.83-0.8
67107.82992.7912.20.912432993.52-0.9
68109.43082.7939.60.939863083.54-0.9
69111.03174.0967.40.967713174.90-0.9
70112.73266.7995.70.995963267.59-0.9
71114.33360.71024.31.024623361.62-0.9

You can see from the table above that over 50 miles it is pretty close, I ended my table on 71 miles and you can see that your approximation gets further and further away.

Now, my rule came about from me sitting with pencil and paper along with basic rules of trigonometry and working it out from first principals. As a result I can explain exactly how it works.

Is your rule something you have found on the internet by any chance, something you feel you have been schooled into believing perhaps?

Lets forget about Earth for a moment. If I asked your to provide a rule for the circular drop of any planet of radius r over a distance of d, what would your formula be?

But if you can't do that, suppose your method is correct, what would be the circular drop on earth be on something the length of a bath? Can you work that out and tell us how much the globe model earth drop by over 1.5m (or 5 feet in ancient language)?
A very good post and easy to understand.
 
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